X^2+29x+204=0

Solution for X^2+29x+204=0 equation:

X^2+29X+204=0

a = 1; b = 29; c = +204;
Δ = b2-4ac
Δ = 292-4·1·204
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-5}{2*1}=\frac{-34}{2}
=-17
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+5}{2*1}=\frac{-24}{2}
=-12
$